contourHSC Mathematics Extension 2 · Loci · Mainstage
Where can z be?
Set a, b and θ. Then hover a point z: the two arguments get subtracted in front of you, and the locus is every z where that difference lands on θ.
abthe locusthe other arcz
Points
Real part on the left, imaginary part on the right. Or drag a and b on the diagram.
Angle θ
π/2
90°
π
Any value from −1 to 1 (a multiple of π). Press Enter to apply.
At the point z
z–arg(z − a)–arg(z − b)–difference–
Difference = θ, so z is on the locus.
Analysis
chord |a − b|–sin θ–radius–centre–arc–arc length–
Show
Presets
The difference is reduced to (−π, π]. The angle marked at z is the anticlockwise turn from the direction of z − b to the direction of z − a. On the other arc that turn is −θ, so those points are not on the locus.
Built for the Term 3 Holidays Workshop (Part II, loci). Scan the QR in your booklet to reopen this page.